Aptitude Logical Reasoning and Analytical Ability

Syllogisms

Syllogisms for CGPSC CSAT: A, E, I, O statements, distribution, conversion, Venn diagrams, validity rules, either-or and possibility conclusions.

14 min read Updated Oct 2026 #syllogisms#logical reasoning#venn diagrams

Prerequisites

The Hook: “Ramu Gets Rice, So Ramu Has a Ration Card?”

Connect

A notice at a fair price shop (उचित मूल्य दुकान) in a village near Kanker reads: “All ration card holders of this panchayat receive rice at this shop.” A villager watches Ramu collect a bag of rice and concludes, “So Ramu must hold a ration card of this panchayat.”

Sounds reasonable — but it does not follow. The notice says every card holder gets rice; it never says that only card holders do. Ramu may be buying under some other arrangement. The notice puts all card holders inside the circle of rice receivers; it says nothing about who else is in that circle.

The question this page answers: given a few statements, how do you decide — mechanically and without trusting your instinct — which conclusions must be true, which only might be true, and which cannot be true?

Why it matters for CGPSC: syllogism (न्याय-वाक्य) questions are a staple of reasoning sections in CSAT-type papers, and the same skill decides inference and assumption questions in comprehension passages. The statements are often deliberately absurd (“All pens are trees”) so that your real-world knowledge cannot help you — only the logic can.

The Four Standard Statements

Every syllogism statement is one of four types. The letters come from Latin logic: A and I from AffIrmo (I affirm), E and O from nEgO (I deny).

TypeFormQuantityQualityExample
AAll S are PUniversalAffirmativeAll officers are graduates.
ENo S is PUniversalNegativeNo officer is a farmer.
ISome S are PParticularAffirmativeSome officers are farmers.
OSome S are not PParticularNegativeSome officers are not farmers.

S is the subject and P is the predicate. In logic, “some” means at least one, possibly all. So “Some officers are graduates” is still true if every officer is a graduate.

Translate everyday wording first
  • “Every / each / any S is P” → A
  • “None of the S is P”, “S is never P” → E
  • “Many / a few / most / at least one S is P” → I
  • “Not all S are P” → O: Some S are not P

“All S are not P” is ambiguous in ordinary English (it can mean “No S is P” or “Not all S are P”). Well-set questions avoid it; if you meet it, read the options to see which sense the setter intends.

The Venn diagram of each type

Draw S and P as circles. Shaded or overlapping regions show what the statement guarantees:

TypeBasic diagramWhat it guarantees
A: All S are PS circle fully inside PNo part of S lies outside P
E: No S is PS and P separateNo overlap at all
I: Some S are PS and P overlapAt least one element in the overlap
O: Some S are not PPart of S outside PAt least one S lies outside P

An A statement can also be drawn with S and P as the same circle (all S are P and all P are S). Since “All S are P” does not rule this out, it remains a possible case — one of the reasons possibility questions exist.

Distribution: Which Term Is “Fully Covered”?

A term is distributed when the statement says something about every member of it.

TypeSubject distributed?Predicate distributed?
A — All S are PYesNo
E — No S is PYesYes
I — Some S are PNoNo
O — Some S are not PNoYes

“All officers are graduates” tells you about every officer but not about every graduate, so only the subject is distributed. “No officer is a farmer” tells you about every officer and every farmer (none of them is an officer), so both are distributed.

Conversion (Immediate Inference)

Conversion swaps subject and predicate. Only some conversions are valid:

StatementValid conversionNote
All S are P (A)Some P are S (I)Never “All P are S”
No S is P (E)No P is S (E)Fully reversible
Some S are P (I)Some P are S (I)Fully reversible
Some S are not P (O)NoneO cannot be converted
Worked example: why O cannot be converted
“Some animals are not dogs” is true. Its “conversion”, “Some dogs are not animals”, is false. One counter-example is enough to show the conversion is invalid.

Combining Two Statements

When two statements share a middle term (the term that appears in both but not in the conclusion), write them so the middle term sits at the end of the first and the start of the second: X–Y, Y–Z. Then read the conclusion from this table. A “+” means “first statement, then second”.

First + Second (aligned X–Y, Y–Z)Definite conclusion
A + AAll X are Z (A)
A + ENo X is Z (E)
E + ASome Z are not X (O, reversed)
E + ISome Z are not X (O, reversed)
I + ASome X are Z (I)
I + ESome X are not Z (O)
A + I, I + I, E + E, any pair with ONo definite conclusion between X and Z

Each conclusion can then be converted using the conversion table: from “All X are Z” you also get “Some Z are X”; from “No X is Z”, “No Z is X”.

The six classical rules behind the table
  1. Two particular statements (I, O) → no conclusion.
  2. Two negative statements (E, O) → no conclusion.
  3. If one statement is negative, the conclusion must be negative.
  4. If one statement is particular, the conclusion must be particular.
  5. The middle term must be distributed in at least one statement.
  6. A term not distributed in the statements cannot be distributed in the conclusion.

A + I fails rule 5: in “All X are Y” and “Some Y are Z”, Y is distributed in neither statement.

Worked example 1

Statements: All teachers are graduates. All graduates are voters. Conclusions: I. All teachers are voters. II. Some voters are teachers.

A + A gives “All teachers are voters” — I follows. Converting it gives “Some voters are teachers” — II follows. Both follow.

Worked example 2

Statements: Some farmers are traders. No trader is a clerk. Conclusions: I. Some farmers are not clerks. II. No farmer is a clerk.

I + E gives “Some farmers are not clerks” — I follows. II is not forced: the farmers who are not traders may or may not be clerks. Only I follows.

“Either I or II”: Complementary Pairs

Sometimes neither conclusion follows on its own, yet in every possible diagram at least one of them is true. The answer is then “Either I or II follows”. This happens when all three conditions hold:

  1. Both conclusions have the same subject and predicate.
  2. Neither follows individually.
  3. They form an I–O, A–O or E–I pair.
Worked example 3

Statements: All mangoes are fruits. Some fruits are sweet. Conclusions: I. Some mangoes are sweet. II. Some mangoes are not sweet.

A + I gives no definite conclusion, so neither I nor II follows alone. But they share subject and predicate and form an I–O pair: either some mangoes fall in the “sweet” circle, or some fall outside it (or both). Either I or II follows.

“Possibility” Conclusions

Modern question setters often ask whether something “is a possibility”. The test changes:

Conclusion typeIt follows if…
Definite (“All A are C”, “Some A are C”)True in every diagram consistent with the statements
Possibility (“All A being C is a possibility”)True in at least one diagram consistent with the statements

A possibility conclusion fails only when it would contradict a statement or a definite conclusion.

Worked example 4

Statements: All rivers are streams. No stream is a pond. Conclusions: I. No river is a pond. II. Some ponds being rivers is a possibility.

A + E gives “No river is a pond” — I follows definitely. II asks for a diagram where a pond overlaps a river; but every river sits inside “streams”, and streams and ponds never meet. II contradicts a definite conclusion. Only I follows.

The Method in Five Steps

graph TD
    A[Read each statement and label A/E/I/O] --> B[Draw the basic Venn diagram]
    B --> C[Check each conclusion: true in EVERY diagram?]
    C -->|Yes| D[Follows]
    C -->|No| E[Possibility conclusion? Can ANY diagram make it true?]
    E --> F[Finally test unresolved pairs for Either-Or]

Memory Tricks

Anchor these
  • “AffIrmo, nEgO”. A and I affirm; E and O deny.
  • “US-NP” (think “US News Paper”). Universals (A, E) distribute the Subject; Negatives (E, O) distribute the Predicate.
  • Conversion: “A shrinks, E and I swap freely, O stays stuck.” All S are P → Some P are S; E and I reverse as they are; O never converts.
  • The six winning pairs: “AA, AE, EA, EI, IA, IE”. Any other pairing (and anything with O) gives no definite conclusion. When E comes first (EA, EI), the conclusion is reversed: Some Z are not X.
  • “Some” means “at least one, maybe all”. Say it every time you see “some”.

Don’t Confuse

ThisvsThat
All S are P → Some P are S (valid)All S are P → All P are S (invalid)
“Some S are P” — true even if all S are PEveryday “some” — implies “not all”
Definite conclusion — true in every diagramPossibility — true in at least one diagram
Either-or needs same subject and predicateSome A are B / Some B are not A — not a complementary pair
A + E → No X is ZE + A → Some Z are not X (reversed O)

Common Mistakes

Trap 1: Using real-world knowledge
“All chairs are rivers. All rivers are books.” Absurd statements are deliberate. Treat them as true and work only with the diagram; “All chairs are books” follows even though it is nonsense in real life. Equally, a conclusion that is true in real life but not forced by the statements does not follow.
Trap 2: Reversing an A statement
From “All officers are graduates” you cannot get “All graduates are officers”. The hook’s ration-card error is exactly this mistake. The valid conversion is only “Some graduates are officers”.
Trap 3: Marking 'Either-or' too quickly
“Either I or II” applies only when neither follows on its own. If one of the pair already follows definitely, the answer is “Only I” (or “Only II”), not “Either”.

Practice

Level 1: Foundation

  1. Classify: “No tiger is a herbivore.”
  2. Classify: “Some officers are not punctual.”
  3. Write the valid conversion of “Some teachers are poets.”
  4. In “All S are P”, which term is distributed?
  5. What do you get from: All A are B; No B is C?
Answers
  1. E (universal negative).
  2. O (particular negative).
  3. Some poets are teachers.
  4. Only the subject S.
  5. No A is C (A + E), and by conversion No C is A.

Level 2: Prelims MCQs

For Q1, Q3 and Q5, take the statements as true even if they seem to differ from common knowledge.

Q1. Statements: Some officers are graduates. All graduates are voters. Conclusions: I. Some officers are voters. II. Some voters are officers.

(a) Only I follows (b) Only II follows (c) Neither I nor II follows (d) Both I and II follow

Answer: (d) Both I and II follow
I + A gives “Some officers are voters”, so I follows. Converting an I statement is always valid, giving “Some voters are officers”, so II also follows.

Q2. Consider the following statements about conversion:

  1. “Some A are not B” can be validly converted to “Some B are not A”.
  2. “No A is B” can be validly converted to “No B is A”.
  3. “All A are B” can be validly converted to “Some B are A”.

Which of the statements given above is/are correct?

(a) 1 only (b) 2 and 3 only (c) 1 and 3 only (d) 1, 2 and 3

Answer: (b) 2 and 3 only
E statements convert simply (statement 2 is correct), and A statements convert only to I (statement 3 is correct). O statements cannot be converted at all: “Some animals are not dogs” is true, but “Some dogs are not animals” is false. So statement 1 is wrong.

Q3. Statements: All officers are graduates. Some graduates are farmers. No farmer is lazy. Conclusions: I. Some officers are lazy. II. Some officers are not lazy.

(a) Only I follows (b) Only II follows (c) Either I or II follows (d) Neither I nor II follows

Answer: (c) Either I or II follows

Officers are linked to graduates by A, but graduates link to farmers only by I (A + I gives nothing), so nothing definite connects officers to lazy people. Neither conclusion follows alone. But I and II have the same subject (officers) and predicate (lazy) and form an I–O pair: in any diagram, either some officers are lazy, or some are not (or both). So “Either I or II”.

Note that “Some graduates are not lazy” (I + E) would follow — a likely option in a different version of this question.

Q4. Match the statement types in List I with the terms they distribute in List II:

List I (Type)List II (Distributes)
A. All S are P1. Neither term
B. No S is P2. Predicate only
C. Some S are P3. Subject only
D. Some S are not P4. Both subject and predicate

(a) A-3, B-4, C-1, D-2 (b) A-3, B-4, C-2, D-1 (c) A-4, B-3, C-1, D-2 (d) A-1, B-4, C-3, D-2

Answer: (a) A-3, B-4, C-1, D-2
Use “US-NP”: universals (A, E) distribute the subject; negatives (E, O) distribute the predicate. A is universal only → subject. E is universal and negative → both. I is neither → no term. O is negative only → predicate.

Q5. Statements: No pen is a pencil. All pencils are erasers. Conclusions: I. No eraser is a pen. II. Some erasers are not pens.

(a) Only I follows (b) Only II follows (c) Either I or II follows (d) Neither I nor II follows

Answer: (b) Only II follows
E + A gives the reversed O conclusion: “Some erasers are not pens” (the erasers that are pencils are certainly not pens). So II follows. I does not: erasers that are not pencils may well be pens. Since II already follows, “Either” is wrong — Trap 3.

Level 3: Speed Drill — Solve in 60 Seconds

Prelims Paper II rewards speed, and the reasoning part of Mains Paper IV (GS-II) expects the same logic with the steps shown — for syllogisms, that means naming the statement types and the rule used. Each item below should take under 60 seconds.

  1. All A are B; all B are C. Does “Some C are A” follow?
  2. Some A are B; some B are C. Does “Some A are C” follow?
  3. No A is B; all B are C. What definite conclusion links A and C?
  4. All A are B; no B is C. What definite conclusion links A and C?
  5. Some A are not B. What is its valid conversion?
  6. Some A are B; no B is C. What definite conclusion links A and C?
Answers with the rule used
  1. Yes — A + A gives All A are C; convert to Some C are A.
  2. No — I + I (two particulars) gives no conclusion.
  3. Some C are not A — E + A gives the reversed O.
  4. No A is C (and No C is A) — A + E gives E.
  5. None — an O statement cannot be converted.
  6. Some A are not C — I + E gives O.

Quick Revision Table

IdeaRule
A / E / I / OAll S are P / No S is P / Some S are P / Some S are not P
“Some”At least one, possibly all
DistributionUniversals → subject; negatives → predicate
ConversionA → I; E → E; I → I; O → none
Valid pairs (aligned X–Y, Y–Z)AA → A; AE → E; EA → O*; EI → O*; IA → I; IE → O (* reversed: Some Z are not X)
No conclusionTwo particulars; two negatives; middle term undistributed
Either-orSame subject and predicate; neither follows alone; I–O, A–O or E–I pair
PossibilityFollows unless it contradicts a statement or a definite conclusion

Key Takeaways

Key Takeaways
  1. Classify every statement as A, E, I or O before doing anything else.
  2. A conclusion follows only if it is true in every diagram; a possibility needs just one.
  3. “All S are P” never reverses into “All P are S” — it converts only to “Some P are S”; O never converts.
  4. Only six pairings give a definite conclusion: AA, AE, EA, EI, IA, IE.
  5. Check for “Either I or II” last, and only when neither conclusion follows on its own.

What’s Next

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